Find the area enclosed by the figure (ii) given below. All measurements are in centimeters.
Mensuration
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Question

Find the area enclosed by the figure (ii) given below. All measurements are in centimeters.

KnowledgeBoat · Accepted Answer

From figure, BJ = 2 + 2 + 2 + 2 = 8 cm. Area of rectangle ABJK = l × b = AB × BJ = 2 × 8 = 16 cm². From figure, JH = KH - KI = 6 - 2 = 4 cm. Area of trapezium FGHI = (sum of parallel sides) × distance between them = × (FI + GH) × JH = × (2 + 2) × 4 = × 4 × 4 = 8 cm². Area of trapezium CDEF = (sum of parallel sides) × distance between them = × (CF + DE) × BD = × (2 + 2) × 4 = × 4 × 4 = 8 cm². Total area enclosed = Area of rectangle ABJK + Area of trapezium FGHI + Area of trapezium CDEF = 16 + 8 + 8 = 32 cm². Hence, area enclosed by figure = 32 cm².

Mathematics

Find the area enclosed by the figure (ii) given below. All measurements are in centimeters.

Mensuration

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