Find the area of the quadrilateral field ABCD whose sides AB = 40 m, BC = 28 m, CD = 15 m, AD = 9 m and ∠A = 90°.

From figure, ABCD is a quadrilateral field. In triangle BAD, ∠A = 90° Using the Pythagoras Theorem ⇒ BD 2 = AB 2 + AD 2 Substituting the values we get, ⇒ BD 2 = 40 2 + 9 2 ⇒ BD 2 = 1600 + 81 = 1681 ⇒ BD = = 41 m We know that, Area of quadrilateral ABCD = Area of △BAD + Area of △BDC Calculating area of △BDC, In △BDC, Let a = BD = 41 m, b = BC = 28 m and c = CD = 15 m. Semi-perimeter (s) = = 42 m. By Heron's formula, Area of triangle = Substituting values we get, Calculating area of △BAD, Area of quadrilateral ABCD = Area of △BAD + Area of △BDC = 180 + 126 = 306 m 2 . Hence, area of quadrilateral ABCD = 306 m 2 .

Find the area of quadrilateral whose one diagonal is 20 cm long and the perpendiculars to this diagonal from other vertices are of length 9 cm and 15 cm.

View Answer Bookmark Now

Find the area of a quadrilateral whose diagonals are of length 18 cm and 12 cm and they intersect each other at right angles.

View Answer Bookmark Now

Find the area of the quadrilateral ABCD in which ∠BCA = 90°, AB = 13 cm and ACD is an equilateral triangle of side 12 cm.

View Answer Bookmark Now

Find the area of quadrilateral ABCD in which ∠B = 90° , AB = 6 cm, BC = 8 cm and CD = AD = 13 cm.

View Answer Bookmark Now

Mathematics

Find the area of the quadrilateral field ABCD whose sides AB = 40 m, BC = 28 m, CD = 15 m, AD = 9 m and ∠A = 90°.

Mensuration

Related Questions

Find the area of quadrilateral whose one diagonal is 20 cm long and the perpendiculars to this diagonal from other vertices are of length 9 cm and 15 cm.

Find the area of a quadrilateral whose diagonals are of length 18 cm and 12 cm and they intersect each other at right angles.

Find the area of the quadrilateral ABCD in which ∠BCA = 90°, AB = 13 cm and ACD is an equilateral triangle of side 12 cm.

Find the area of quadrilateral ABCD in which ∠B = 90° , AB = 6 cm, BC = 8 cm and CD = AD = 13 cm.