Find the compound ratio of 2a : 3b, mn : x² and x : n

Compound ratio of 2a : 3b, mn : x² and x : n,

$= \dfrac{2a}{3b} \times \dfrac{mn}{x^2} \times \dfrac{x}{n} \\[1em] = \dfrac{2amnx}{3bx^2n} \\[1em] = \dfrac{2am}{3bx} = 2am : 3bx.$

Hence, compound ratio of 2a : 3b, mn : x² and x : n is 2am : 3bx.