Find the cube of:

3b - 2a

(3b - 2a)³

Using the formula,

(x - y)³ = x³ - y³ - 3x²y + 3xy²

= (3b)³ - (2a)³ + 3 $\times$ (3b)² $\times$ (2a) + 3 $\times$ (3b) $\times$ (2a)²

= 27b³ - 8a³ - 54b²a + 36ba²

Hence, (3b - 2a)³ = 27b³ - 8a³ - 54b²a + 36ba²