Find the cube-root of 64.

Finding prime factors of 64:

$\sqrt[3]{64}\\[1em] = \sqrt[3]{(2 \times 2 \times 2)\times (2 \times 2 \times 2)}\\[1em] = 2 \times 2\\[1em] = 4$

Hence, $\sqrt[3]{64} = 4$