Find the cube-roots of 64 x 27

Prime factors of 64:

Prime factors of 27:

$\sqrt[3]{64 \times 27}\\[1em] = \sqrt[3]{64}\times{\sqrt[3]{27}}\\[1em] = \sqrt[3]{(2 \times 2 \times 2)\times(2 \times 2 \times 2)}\times{\sqrt[3]{(3 \times 3 \times 3)}}\\[1em] = (2 \times 2)\times(3)\\[1em] = 4\times3\\[1em] = 12$

Hence, $\sqrt[3]{64 \times 27} = 12$