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Mathematics

Find the digits A and B, if :

1B×B9B\begin{matrix} & 1 & \text{B} \ & \times & \text{B} \ \hline & 9 & \text{B} \ \hline \end{matrix}

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Answer

1B×B9B\begin{matrix} & 1 & \text{B} \ & \times & \text{B} \ \hline & 9 & \text{B} \ \hline \end{matrix}

Clearly, B x B = B

1 x 1 = 1

5 x 5 = 25

6 x 6 = 36

So, possible answer for B = 1 or 5 or 6.

But 1 and 5 did not satisfy the multiplication.

136×696\begin{matrix} & \overset{3}{1} & \text{6} \ & \times & \text{6} \ \hline & 9 & \text{6} \ \hline \end{matrix} Hence, B = 6.

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