Find the digits A and B, if : 2 A B + A B 1 = B 1 8

Firstly, we will find the value of B Clearly, B + 1 is a number whose ones digit is 8. ⇒ B + 1 = 8 , B + 1 = 18 , B + 1 = 28; and so on. ⇒ B = 8 - 1 , B = 18 - 1, B = 28 - 1; and so on. ⇒ B = 7 , B = 17, B = 27; and so on. Since, B is a digit. ∴ B = 7 Now, we find the value of A. Clearly, A + 7 is a number whose ones digit is 1. ⇒ A + 7 = 1 , A + 7 = 11 , A + 7 = 21; and so on. ⇒ A = 1 - 7 , A = 11 - 7, A = 21 - 7; and so on. ⇒ A = -6 , A = 4, A = 14; and so on. Since, A is a digit. ∴ A = 4 Hence, A = 4 and B = 7.

In a 3-digit number, the ten's digit is thrice the unit digit and hundred's digit is twice the unit digit. If the sum of all the three digits is 12, find the number.

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Find the digits A and B, if : 2 A B + A B 1 = B 1 8

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In a 3-digit number, the ten's digit is thrice the unit digit and hundred's digit is twice the unit digit. If the sum of all the three digits is 12, find the number.