Find the digits A, B and C, if 7 3 A - B C 9 = 3 4 8

Firstly, we will find the value of A. Clearly, A - 9 is a number whose ones digit is 8. ⇒ A - 9 = 8 , A - 9 = 18 , A - 9 = 28; and so on. ⇒ A = 8 + 9 , A = 18 + 9 , A = 28 + 9; and so on. ⇒ A = 17 , A = 27 , A = 37; and so on. Since, A is a digit. ∴ A = 7. Secondly, we will find the value of C. Clearly, 2 - C is a number whose ones digit is 4. As it is not possible to subtract any number from 2 that gives 4. Hence, borrowing one number from preceding digit gives 12 - C. ⇒ 12 - C = 4 , 12 - C = 14 , 12 - C = 24; and so on. ⇒ C = 12 - 4 , C = 12 - 14 , C = 12 - 24; and so on. ⇒ C = 8 , C = -2 , C = -12; and so on. Since, C is a digit. ∴ C = 8. Lastly, we will find the value of B. Clearly, 6 - B is a number whose ones digit is 3. ⇒ 6 - B = 3 , 6 - B = 13 , 6 - B = 23; and so on. ⇒ B = 6 - 3 , B = 6 - 13 , B = 6 - 23; and so on. ⇒ B = 3 , B = -7 , B = -17; and so on. Since, B is a digit. ∴ B = 3. Hence, A = 7, B = 3 and C = 8.

If 31y5 is divisible by 3, find the value(s) of digit y.

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In a 3-digit number, the ten's digit is thrice the unit digit and hundred's digit is twice the unit digit. If the sum of all the three digits is 12, find the number.

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Find the digits A, B and C, if 7 3 A - B C 9 = 3 4 8

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If 31y5 is divisible by 3, find the value(s) of digit y.

In a 3-digit number, the ten's digit is thrice the unit digit and hundred's digit is twice the unit digit. If the sum of all the three digits is 12, find the number.