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Chemistry

Find the empirical formula of the compounds with the following percentage composition:

Pb = 62.5%, N = 8.5%, O = 29.0%

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Answer

Element% compositionAt. massRelative no. of atomsSimplest ratio
Pb62.520762.5207\dfrac{62.5 }{207} = 0.3010.3010.301\dfrac{0.301}{0.301 } = 1
N8.5148.514\dfrac{8.5}{14} = 0.6070.6070.301\dfrac{0.607}{0.301 } = 2
O29162916\dfrac{29}{16} = 1.811.810.301\dfrac{1.81}{0.301 } = 6

Hence, Simplest ratio of whole numbers = Pb : N : O = 1 : 2 : 6

Hence, empirical formula is Pb(NO3)2.

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