Find the equation of the line whose slope is -4/3 and which passes through (-3, 4).

Question

KnowledgeBoat · Accepted Answer

By point-slope form, Equation of line : y - y₁ = m(x - x₁) Substituting values we get, ⇒ y - 4 = [x - (-3)] ⇒ 3(y - 4) = -4(x + 3) ⇒ 3y - 12 = -4x - 12 ⇒ 4x + 3y = -12 + 12 ⇒ 4x + 3y = 0. Hence, equation of line is 4x + 3y = 0.

Mathematics

Find the equation of the line whose slope is -4/3 and which passes through (-3, 4).

Straight Line Eq

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Find the equation of a line whose :
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Mathematics

Find the equation of the line whose slope is -4/3 and which passes through (-3, 4).

Straight Line Eq

Related Questions

Find the equation of a line whose :y-intercept = -1 and inclination = 45°.

Find the equation of a line which passes through (5, 4) and makes an angle of 60° with the positive direction of the x-axis.

Find the equation of a line passing through :(i) (0, 1) and (1, 2)(ii) (-1, -4) and (3, 0)

Find the equation of a line whose :
y-intercept = -1 and inclination = 45°.

Find the equation of a line passing through :
(i) (0, 1) and (1, 2)
(ii) (-1, -4) and (3, 0)