Find the equation of the line, whose : x-intercept = -4 and y-intercept = 6

x-intercept = -4 and y-intercept = 6 When x-intercept = -4; corresponding point on the x-axis = (-4, 0) When y-intercept = 6; corresponding point on the y-axis = (0, 6). By point-slope form, ⇒ y - y 1 = m(x - x 1 ) ⇒ y - 0 = [x - (-4)] ⇒ y = (x + 4) ⇒ 2y = 3x + 12 ⇒ 2y - 3x = 12 ⇒ 2y = 3x + 12 Hence, equation of line is 2y = 3x + 12.