Find the equation of the line, whose : x-intercept = 5 and y-intercept = 3

x-intercept = 5 and y-intercept = 3 When x-intercept = 5; corresponding point on the x-axis = (5, 0) When y-intercept = 3; corresponding point on the y-axis = (0, 3). By point-slope form, ⇒ y - y 1 = m(x - x 1 ) ⇒ y - 0 = (x - 5) ⇒ 5y = -3(x - 5) ⇒ 5y = -3x + 15 ⇒ 3x + 5y = 15. Hence, equation of line is 3x + 5y = 15.