Find the geometric progression whose 5 th term is 48 and 8 th term is 384.

Let first term of G.P. be a and common ratio be r. By formula, ⇒ a n = ar n - 1 ⇒ a 5 = ar 5 - 1 ⇒ 48 = ar 4 ........(1) ⇒ a 8 = 384 ⇒ ar 8 - 1 = 384 ⇒ ar 7 = 384 ........(2) Dividing equation (2) by (1), we get : Substituting value of r in equation (1), we get : ⇒ a(2) 4 = 48 ⇒ 16a = 48 ⇒ a = = 3. G.P. = a, ar, ar 2 , ......... = 3, 3 × 2, 3 × 2 2 , ........ = 3, 6, 12, ...... Hence, G.P. = 3, 6, 12, ......

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Mathematics

Find the geometric progression whose 5^th term is 48 and 8^th term is 384.

AP GP

Related Questions

If the sum of first n terms of an A.P. is 3n² + 2n, find its r^th term.

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Mathematics

Find the geometric progression whose 5th term is 48 and 8th term is 384.

AP GP

Related Questions

If the sum of first n terms of an A.P. is 3n2 + 2n, find its rth term.

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Find the sum of n terms of the sequence : 5 + 55 + 555 + …….

Find the geometric progression whose 5^th term is 48 and 8^th term is 384.

If the sum of first n terms of an A.P. is 3n² + 2n, find its r^th term.