Find the interest and the amount on:

₹ 750 in 3 years 4 months at 10% per annum.

Given:

P = ₹ 750

R = 10%

T = 3 years 4 months

= $\Big(3 + \dfrac{4}{12}\Big)$ years

= $\Big(3 + \dfrac{1}{3}\Big)$ years

= $\dfrac{10}{3}$ years

$\because \text{S.I.} = ₹ \Big(\dfrac{P \times R \times T}{100}\Big)\\[1em] \Rightarrow \text{S.I.} = ₹ \Big(\dfrac{750 \times 10 \times 10}{3 \times 100}\Big)\\[1em] \Rightarrow \text{S.I.} = ₹ \Big(\dfrac{75,000}{300}\Big)\\[1em] \Rightarrow \text{S.I.} = ₹ 250 \\[2em] \because \text{A = P + S.I.}\\[1em] \Rightarrow \text{A = ₹ 750 + ₹ 250}\\[1em] \Rightarrow \text{A = ₹ 1,000}\\[1em]$

Hence, S.I. = ₹ 250 and Amount = ₹ 1,000.