Mathematics

Find the logarithm of 32 to the base 4.

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Let,

⇒ log₄ 32 = x

⇒ 32 = 4^x

⇒ (2)⁵ = (2²)^x

⇒ (2)⁵ = (2)^2x

⇒ 2x = 5

⇒ x = $\dfrac{5}{2}$ .

Hence, required value = $\dfrac{5}{2}$ .

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