Find the point on the x-axis which is equidistant from the points (2, -5) and (-2, 9).

We know that, y-coordinate of any point on x-axis = 0. By distance formula, d = Let point on x-axis which is equidistant from the points (2, -5) and (-2, 9) be P(x, 0). ∴ Distance between (2, -5) and (x, 0) = Distance between (-2, 9) and (x, 0). On squaring both sides, P = (x, 0) = (-7, 0). Hence, required point is (-7, 0).