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Mathematics

Find the quotient and the remainder (if any), when:

6x2 + x - 15 is divided by 3x + 5.

Algebraic Expressions

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Answer

(6x2 + x - 15) ÷ (3x + 5)

Dividing 6x2 + x - 15 by 3x + 5

3x+5)2x33x+5)6x2+x153x+56x2+10x3x+56x2+9x153x+56x2++9x+153x+56x2+9x×\begin{array}{l} \phantom{3x + 5)}{2x - 3} \ 3x + 5\overline{\smash{\big)}6x^2 + x - 15} \ \phantom{3x + 5}\underline{\underset{-}{}6x^2 \underset{-}{+}10x} \ \phantom{{3x + 5}6x^2 +}-9x - 15 \ \phantom{{3x + 5}6x^2 +}\underline{\underset{+}{-}9x \underset{+}{-} 15} \ \phantom{{3x + 5}6x^2 + 9x -} \times \end{array}

Quotient = 2x - 3

Remainder = 0

Verification:

Quotient x Divisor + Remainder

= (2x - 3) ×\times (3x + 5) + 0

= 2x ×\times (3x + 5) - 3 ×\times (3x + 5)

= 6x(1+1) + 10x - 9x - 15

= 6x2 + (10x - 9x) - 15

= 6x2 + x - 15

= Dividend

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