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Mathematics

Find the reciprocal ratio of :

(i) 4 : 7

(ii) 32 : 42

(iii) 19:2\dfrac{1}{9} : 2

Ratio Proportion

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Answer

(i) The reciprocal ratio of 4 : 7 is,

=14:17=1417=74=7:4= \dfrac{1}{4} : \dfrac{1}{7} \\[0.5em] = \dfrac{\dfrac{1}{4}}{\dfrac{1}{7}} \\[0.5em] = \dfrac{7}{4} \\[0.5em] = 7 : 4

Hence, the reciprocal ratio is 7 : 4.

(ii) The reciprocal ratio of 32 : 42 is,

=132:142=19116=169=16:9= \dfrac{1}{3^2} : \dfrac{1}{4^2} \\[0.5em] = \dfrac{\dfrac{1}{9}}{\dfrac{1}{16}} \\[0.5em] = \dfrac{16}{9} \\[0.5em] = 16 : 9

Hence, the reciprocal ratio is 16 : 9.

(iii) The reciprocal ratio of 19:2\dfrac{1}{9} : 2 is,

=119:12=912=181=18:1= \dfrac{1}{\dfrac{1}{9}} : \dfrac{1}{2} \\[0.5em] = \dfrac{9}{\dfrac{1}{2}} \\[0.5em] = \dfrac{18}{1} \\[0.5em] = 18 : 1

Hence, the reciprocal ratio is 18 : 1.

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