Find the smallest square number which is divisible by 6, 9 and 15.
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LCM of 6, 9 and 15 is 2 x 3 x 3 x 5 = 90
As 2 and 5 are not in pair. To make it a perfect square, it must be multiplied with 2 x 5 = 10.
∴ Required perfect square = 90 x 10 = 900.
The smallest square number which is divisible by 6, 9 and 15 is 900.
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