Find the square root of $96\dfrac{1}{25}$.

$\sqrt{96\dfrac{1}{25}} = \sqrt{\dfrac{2401}{25}}\\[1em] = \dfrac{\sqrt{2401}}{\sqrt{25}}\\[1em] = \dfrac{\sqrt{(7\times7)\times(7\times7)}}{\sqrt{(5\times5)}}\\[1em] = \dfrac{7\times7}{5}\\[1em] = \dfrac{49}{5}\\[1em] = 9\dfrac{4}{5}$

$\sqrt{96\dfrac{1}{25}} = 9\dfrac{4}{5}$