Find the sum of first positive 1000 integers.

We need to find 1 + 2 + 3 + 4 + ...... + 1000 The above series is an A.P. with first term a = 1, d = 1 and n = 1000. By formula S n = ⇒ S 1000 = ⇒ S 1000 = 500[2 + 999] ⇒ S 1000 = 500 × 1001 ⇒ S 1000 = 500500. Hence, the sum of first 1000 positive integers is 500500.

In an A.P., the sum of its first n terms is 6n - n². Find its 25th term.

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If S_n denotes the sum of first n terms of an A.P., prove that S₃₀ = 3(S₂₀ - S₁₀).

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Find the sum of first 15 multiples of 8.

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Find the sum of all two digit natural numbers which are divisible by 4.

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Mathematics

Find the sum of first positive 1000 integers.

AP GP

Related Questions

In an A.P., the sum of its first n terms is 6n - n². Find its 25th term.

If S_n denotes the sum of first n terms of an A.P., prove that S₃₀ = 3(S₂₀ - S₁₀).

Find the sum of first 15 multiples of 8.

Find the sum of all two digit natural numbers which are divisible by 4.

Mathematics

Find the sum of first positive 1000 integers.

AP GP

Related Questions

In an A.P., the sum of its first n terms is 6n - n2. Find its 25th term.

If Sn denotes the sum of first n terms of an A.P., prove that S30 = 3(S20 - S10).

Find the sum of first 15 multiples of 8.

Find the sum of all two digit natural numbers which are divisible by 4.

In an A.P., the sum of its first n terms is 6n - n². Find its 25th term.

If S_n denotes the sum of first n terms of an A.P., prove that S₃₀ = 3(S₂₀ - S₁₀).