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Mathematics

Find the sum of G.P. :

0.3 + 0.03 + 0.003 + 0.0003 + …… to 8 terms.

GP

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Answer

Common ratio (r) = 0.030.3\dfrac{0.03}{0.3} = 0.1

S=a(1rn)(1r)..........(Asr<1)=0.3[1(0.1)8]10.1=0.3[1(110)8]0.9=13(11108).S = \dfrac{a(1 - r^n)}{(1 - r)} ……….(As |r| \lt 1)\\[1em] = \dfrac{0.3\Big[1 - (0.1)^8\Big]}{1 - 0.1} \\[1em] = \dfrac{0.3\Big[1 - \Big(\dfrac{1}{10}\Big)^8\Big]}{0.9} \\[1em] = \dfrac{1}{3}\Big(1 - \dfrac{1}{10^8}\Big).

Hence, sum = 13(11108)\dfrac{1}{3}\Big(1 - \dfrac{1}{10^8}\Big).

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