Mathematics

Find the value of k for the following quadratic equation, so that it has two equal roots.
2x² + kx + 3 = 0

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Comparing 2x² + kx + 3 = 0 with ax² + bx + c = 0, we get :

a = 2, b = k and c = 3.

For equal roots,

⇒ b² - 4ac = 0

⇒ k² - 4 × 2 × 3 = 0

⇒ k² - 24 = 0

⇒ k² = 24

⇒ k = $\sqrt{24}$

⇒ k = $\pm 2\sqrt{6}$

Hence, k = $\pm 2\sqrt{6}$ .

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