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Find the values of x, which satisfy the inequation 256<122x32-2\dfrac{5}{6} \lt \dfrac{1}{2} - \dfrac{2x}{3} \le 2, x ∈ W. Graph the solution set on the number line.

Linear Inequations

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Answer

Given,

256<122x32-2\dfrac{5}{6} \lt \dfrac{1}{2} - \dfrac{2x}{3} \le 2

Solving L.H.S. of the inequation,

256<122x3176<122x32x3<12+1762x3<3+1762x3<206x<206×32x<5…….(i)\Rightarrow -2\dfrac{5}{6} \lt \dfrac{1}{2} - \dfrac{2x}{3} \\[1em] \Rightarrow -\dfrac{17}{6} \lt \dfrac{1}{2} - \dfrac{2x}{3} \\[1em] \Rightarrow \dfrac{2x}{3} \lt \dfrac{1}{2} + \dfrac{17}{6} \\[1em] \Rightarrow \dfrac{2x}{3} \lt \dfrac{3 + 17}{6} \\[1em] \Rightarrow \dfrac{2x}{3} \lt \dfrac{20}{6} \\[1em] \Rightarrow x \lt \dfrac{20}{6} \times \dfrac{3}{2} \\[1em] \Rightarrow x \lt 5 …….(i)

Solving R.H.S. of the inequation,

122x322x31222x332x32×32x94x2.25……..(ii)\Rightarrow \dfrac{1}{2} - \dfrac{2x}{3} \le 2 \\[1em] \Rightarrow \dfrac{2x}{3} \ge \dfrac{1}{2} - 2 \\[1em] \Rightarrow \dfrac{2x}{3} \ge -\dfrac{3}{2} \\[1em] \Rightarrow x \ge -\dfrac{3}{2} \times \dfrac{3}{2} \\[1em] \Rightarrow x \ge -\dfrac{9}{4} \\[1em] \Rightarrow x \ge -2.25 ……..(ii)

From (i) and (ii) we get,

-2.25 ≤ x < 5

Since, x ∈ W,

∴ Solution set = {0, 1, 2, 3, 4}.

Solution on the number line is :

Find the values of x, which satisfy the inequation -2(5/6) < (1/2) - (2x/3) ≤ 2, x ∈ W. Graph the solution set on the number line. Linear Inequations, Concise Mathematics Solutions ICSE Class 10.

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