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Mathematics

Find the value of k, if the points (5, k) and (k, 7) are equidistant from point (2, 4).

Distance Formula

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Answer

Given (2, 4) is equidistant from (5, k) and (k, 7).

i.e. distance between (2, 4) and (5, k) = distance between (2, 4) and (k, 7)

(25)2+(4k)2=(2k)2+(47)2(25)2+(4k)2=(2k)2+(47)2(3)2+(4k)2=(2k)2+(3)29+16+k28k=4+k24k+925+k28k=13+k24k13+k24k25k2+8k=012+4k=04k=12k=124k=3\sqrt{(2 - 5)^2 + (4 - k)^2} = \sqrt{(2 - k)^2 + (4 - 7)^2}\\[1em] ⇒ (2 - 5)^2 + (4 - k)^2 = (2 - k)^2 + (4 - 7)^2\\[1em] ⇒ (- 3)^2 + (4 - k)^2 = (2 - k)^2 + (- 3)^2\\[1em] ⇒ 9 + 16 + k^2 - 8k = 4 + k^2 - 4k + 9\\[1em] ⇒ 25 + k^2 - 8k = 13 + k^2 - 4k\\[1em] ⇒ 13 + k^2 - 4k - 25 - k^2 + 8k = 0\\[1em] ⇒ - 12 + 4k = 0\\[1em] ⇒ 4k = 12\\[1em] ⇒ k = \dfrac{12}{4}\\[1em] ⇒ k = 3

Hence, the value of k = 3.

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