Find the value of :

$\dfrac{5}{7}$ of $2\dfrac{1}{3}$kg

We have:

$\dfrac{5}{7}$ of $2\dfrac{1}{3}$kg

$2\dfrac{1}{3}\text{ kg} = \dfrac{7}{3}\text{ kg} \hspace{1.5cm}$[Converting mixed to improper fraction]

Now we have:

$\dfrac{5}{7}$ of $\dfrac{7}{3}$ kg

$\begin{array}{ll} = \Big(\dfrac{7}{3} \times \dfrac{5}{7}\Big) \text{ kg} \\ = \Big(\dfrac{1}{3} \times \dfrac{5}{1}\Big) \text{ kg} & \text{[Simplifying 7 and 7 ⇒ Divide by 7 ]} \\ = \Big(\dfrac{1 \times 5}{3 \times 1}\Big) \text{ kg} \\ = \dfrac{5}{3} \text{ kg} \\ = 1\dfrac{2}{3} \text{ kg} & \text{[Converting improper to mixed fraction]} \end{array}$

∴ The answer is $1\dfrac{2}{3}$ kg