Mathematics
Find the value of the quadratic polynomial 7s2 – 4s + 6 if:
(i) s = 0
(ii) s = –3
(iii) s = 4
Polynomials
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Answer
Given quadratic polynomial: 7s2 – 4s + 6
(i) s = 0
Substituting s = 0 in the polynomial:
= 7(0)2 – 4(0) + 6
= 0 – 0 + 6
= 6
∴ Value of the polynomial when s = 0 is 6.
(ii) s = -3
Substituting s = -3 in the polynomial:
= 7(-3)2 – 4(-3) + 6
= 7(9) + 12 + 6
= 63 + 12 + 6
= 81
∴ Value of the polynomial when s = -3 is 81.
(iii) s = 4
Substituting s = 4 in the polynomial:
= 7(4)2 – 4(4) + 6
= 7(16) – 16 + 6
= 112 – 16 + 6
= 102
∴ Value of the polynomial when s = 4 is 102.
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