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Mathematics

Find the volume and surface area of a sphere of radius :

(i) 10.5 cm

(ii) 4.2 cm

Mensuration

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Answer

(i) Given, r = 10.5 cm

Surface area of sphere = 4πr2

=4×227×10.52=4×227×110.25=97027=1386 cm2.= 4 \times \dfrac{22}{7} \times 10.5^2 \\[1em] = 4 \times \dfrac{22}{7} \times 110.25 \\[1em] = \dfrac{9702}{7} \\[1em] = 1386 \text{ cm}^2.

Volume of sphere = 43\dfrac{4}{3} πr3

=43×227×10.53=43×227×1157.625=10187121=4851 cm3.= \dfrac{4}{3} \times \dfrac{22}{7} \times 10.5^3 \\[1em] = \dfrac{4}{3} \times \dfrac{22}{7} \times 1157.625 \\[1em] = \dfrac{101871}{21} \\[1em] = 4851 \text{ cm}^3.

Hence, volume of the sphere is 4851 cm3 and surface area of a sphere is 1386 cm2.

(ii) Given, r = 4.2 cm

Surface area of sphere = 4πr2

=4×227×4.22=4×227×17.64=1552.327=221.76 cm2.= 4 \times \dfrac{22}{7} \times 4.2^2 \\[1em] = 4 \times \dfrac{22}{7} \times 17.64 \\[1em] = \dfrac{1552.32}{7} \\[1em] = 221.76 \text{ cm}^2.

Volume of sphere = 43\dfrac{4}{3} πr3

=43×227×4.23=43×227×74.088=6519.74421=310.464 cm3.= \dfrac{4}{3} \times \dfrac{22}{7} \times 4.2^3 \\[1em] = \dfrac{4}{3} \times \dfrac{22}{7} \times 74.088 \\[1em] = \dfrac{6519.744}{21} \\[1em] = 310.464 \text{ cm}^3.

Hence, volume of the sphere is 310.464 cm3 and surface area of a sphere is 221.76 cm2.

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