Mathematics

Find the weight of a solid cylinder of radius of radius 10.5 cm and height 60 cm, if the material of the cylinder weighs 5 grams per cu. cm

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Given, radius (r) = 10.5 cm and height (h) = 60 cm

By formula,

Volume of cylinder = πr²h

$= \dfrac{22}{7} \times (10.5)^2 \times 60 \\[1em] = \dfrac{22}{7} \times 110.25 \times 60 \\[1em] = \dfrac{145530}{7} \\[1em] = 20790 \text{ cm}^3.$

Given, the material of the cylinder weighs 5 grams per cu.cm

⇒ 1 gram = $\dfrac{1}{1000}$ kg

⇒ 5 gram = $\dfrac{5}{1000}$ kg

∴ Total weight of the cylinder = 20790 × $\dfrac{5}{1000} = \dfrac{103950}{1000} = 103.95$ kg.

Hence, the weight of a solid cylinder is 103.95 kg.

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