Find x, if :
42x = 132\dfrac{1}{32}321
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Given,
⇒42x=132⇒(22)2x=125⇒24x=2−5⇒4x=−5⇒x=−54.\Rightarrow 4^{2x} = \dfrac{1}{32} \\[1em] \Rightarrow (2^2)^{2x} = \dfrac{1}{2^5} \\[1em] \Rightarrow 2^{4x} = 2^{-5} \\[1em] \Rightarrow 4x = -5 \\[1em] \Rightarrow x = -\dfrac{5}{4}.⇒42x=321⇒(22)2x=251⇒24x=2−5⇒4x=−5⇒x=−45.
Hence, x = −54-\dfrac{5}{4}−45.
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Solve for x :
34x + 1 = (27)x + 1
(49)x + 4 = 72 × (343)x + 1
2x+3=16\sqrt{2^{x + 3}} = 162x+3=16
(35)x+1=12527\Big(\sqrt{\dfrac{3}{5}}\Big)^{x + 1} = \dfrac{125}{27}(53)x+1=27125
