KnowledgeBoat Logo
|

Physics

A fire truck uses 10,000 litres of water to extinguish a fire, cooling down the burning material from 500°C to 100°C. If the temperature of water increases by 40°C, how much heat energy is absorbed by it? (Specific heat capacity of water = 4200 J kg⁻¹ K⁻¹)

Calorimetry

89 Likes

Answer

Given,

Volume of water (V) = 10,000 L

Temperature increased (△t) = 40°C = 40 K

Specific heat capacity of water (c) = 4200 J kg⁻¹ K⁻¹

As,

Density of water (d) = 1 Kg/L

d=mVm=dV=1×10000=10000 kgd=\dfrac{m}{V} ⟹ m=dV=1\times10000=10000 \text{ kg}

Let, Heat absorbed is Q.

From relation,
Q=mctQ = m c △t

Substituting the values in the above formula, Q=10,000×4200×40=168×107JQ = 10,000\times4200\times40=168\times10^7 J

Heat absorbed by water is 168 x 107 J.

Answered By

26 Likes


Related Questions