The first term of an A.P. is p and its common difference is q. The 10th term of the A.P. is :

1. p − 9q

2. p + 10q

3. p − 10q

4. p + 9q

Given,

First term = p

Common difference = q

n = 10

We know that,

nth term of A.P. :

∴ T_n = a + (n - 1)d

⇒ T₁₀ = p + (10 - 1)q

= p + 9q.

Hence, option 4 is the correct option.