Mathematics
The following table gives the wages of different categories of workers in a factory :
| Category | Wages in ₹/day | Number of workers |
|---|---|---|
| A | 250 | 2 |
| B | 300 | 4 |
| C | 350 | 8 |
| D | 400 | 12 |
| E | 450 | 10 |
| F | 500 | 6 |
| G | 550 | 8 |
(i) Calculate the mean wage.
(ii) If the number of workers in each category is doubled, what would be the new mean wage?
Measures of Central Tendency
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Answer
| Category | Wages in ₹/day (x) | Number of workers (f) | fx |
|---|---|---|---|
| A | 250 | 2 | 500 |
| B | 300 | 4 | 1200 |
| C | 350 | 8 | 2800 |
| D | 400 | 12 | 4800 |
| E | 450 | 10 | 4500 |
| F | 500 | 6 | 3000 |
| G | 550 | 8 | 4400 |
| Total | ∑fi = 50 | ∑fx= 21200 |
(i) We know that,
n = ∑f = 50.
By formula,
Mean wage = = ₹ 424
Hence, mean wage is ₹ 424.
(ii) If all frequencies in a distribution are multiplied by a constant, the mean remains unchanged.
n = ∑f = 50 x 2 = 100.
∑fx = 21200 x 2 = 42400
By formula,
Mean wage = = ₹ 424
Hence, new mean wage is ₹ 424.
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