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Mathematics

The following table gives the wages of different categories of workers in a factory :

CategoryWages in ₹/dayNumber of workers
A2502
B3004
C3508
D40012
E45010
F5006
G5508

(i) Calculate the mean wage.
(ii) If the number of workers in each category is doubled, what would be the new mean wage?

Measures of Central Tendency

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Answer

CategoryWages in ₹/day (x)Number of workers (f)fx
A2502500
B30041200
C35082800
D400124800
E450104500
F50063000
G55084400
Total∑fi = 50∑fx= 21200

(i) We know that,

n = ∑f = 50.

By formula,

Mean wage = fxn=2120050\dfrac{\sum fx}{n} = \dfrac{21200}{50} = ₹ 424

Hence, mean wage is ₹ 424.

(ii) If all frequencies in a distribution are multiplied by a constant, the mean remains unchanged.

n = ∑f = 50 x 2 = 100.

∑fx = 21200 x 2 = 42400

By formula,

Mean wage = fxn=42400100\dfrac{\sum fx}{n} = \dfrac{42400}{100} = ₹ 424

Hence, new mean wage is ₹ 424.

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