Mathematics
The following table keep the daily wages of worker in a factory
| Wages in ₹ | No. of workers |
|---|---|
| 450 - 500 | 5 |
| 500 - 550 | 8 |
| 550 - 600 | 30 |
| 600 - 650 | 25 |
| 650 - 700 | 14 |
| 700 - 750 | 12 |
| 750 - 800 | 6 |
Calculate the mean by short cut method.
Measures of Central Tendency
10 Likes
Answer
We construct the following table as under taking the assumed mean, a = 625.
| Class | Class - mark (xi) | Frequency (fi) | Deviation (di = xi - a) | fidi |
|---|---|---|---|---|
| 450 - 500 | 475 | 5 | -150 | -750 |
| 500 - 550 | 525 | 8 | -100 | -800 |
| 550 - 600 | 575 | 30 | -50 | -1500 |
| 600 - 650 | 625 | 25 | 0 | 0 |
| 650 - 700 | 675 | 14 | 50 | 700 |
| 700 - 750 | 725 | 12 | 100 | 1200 |
| 750 - 800 | 775 | 6 | 150 | 900 |
| Total | Σfi = 100 | Σfidi = -250 |
By formula,
Hence, mean of the following distribution is ₹622.5.
Answered By
5 Likes
Related Questions
Calculate the mean of the following distribution using step deviation method :
Marks Number of students 0 - 10 10 10 - 20 9 20 - 30 25 30 - 40 30 40 - 50 16 50 - 60 10 The data on the number of patients attending a hospital in a month is given below. Find the average (mean) number of patients attending the hospital in a month using the short cut method.
Take assumed mean as 45. Give your answer correct to 2 decimal places.
Number of patients Number of days 10 - 20 5 20 - 30 2 30 - 40 7 40 - 50 9 50 - 60 2 60 - 70 5 Calculate the mean of the distribution given below using the short cut method.
Marks No. of students 11 - 20 2 21 - 30 6 31 - 40 10 41 - 50 12 51 - 60 9 61 - 70 7 71 - 80 4 A class teacher has the following absentee record of 40 students of a class for the whole term. Find the mean number of days a student was absent.
No. of days No. of students 0 - 6 11 6 - 10 10 10 - 14 7 14 - 20 4 20 - 28 4 28 - 38 3 38 - 40 1