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Mathematics

The following table shows the relationship between the monthly incomes and the number of vehicles in a family. If 2000 families, in a locality, are selected, the information gathered is listed in the table below :

Monthly income (₹)0 vehicle1 vehicle2 or more than 2 vehicles
Less than 10,000114013
10,000 - 12,000228517
12,000 - 14,00005150
14,000 - 16,00004499
16,000 or more35597

A family is chosen, write the probability that the family chosen is :

(i) earning ₹ 10,000 - ₹ 12,000 per month and owning exactly 1 (one) vehicle.

(ii) earning ₹ 14,000 or more per month and owning 2 or more than 2 vehicles.

(iii) not owning more than 1 vehicle.

Probability

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Answer

Total number of families = 2000.

By formula,

Probability of an event = Number of favourable outcomesTotal number of outcomes\dfrac{\text{Number of favourable outcomes}}{\text{Total number of outcomes}}

(i) Number of families earning ₹ 10,000 - ₹ 12,000 per month and owning exactly 1 vehicle = 285.

∴ Required probability = 2852000=57400\dfrac{285}{2000} = \dfrac{57}{400}.

Hence, the required probability = 57400\dfrac{57}{400}.

(ii) Number of families earning ₹ 14,000 or more per month and owning 2 or more vehicles = 9 + 7 = 16.

∴ Required probability = 162000=1125\dfrac{16}{2000} = \dfrac{1}{125}.

Hence, the required probability = 1125\dfrac{1}{125}.

(iii) Families not owning more than 1 vehicle are those owning 0 or 1 vehicle.

Number of such families = (1 + 2 + 0 + 0 + 3) + (140 + 285 + 515 + 449 + 559)

= 6 + 1948 = 1954.

∴ Required probability = 19542000=9771000\dfrac{1954}{2000} = \dfrac{977}{1000}.

Hence, the required probability = 9771000\dfrac{977}{1000}.

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