Mathematics
The following table shows the weights (in gm) of a sample of 100 apples, taken from a large consignment:
| Weight (in gm) | Number of apples |
|---|---|
| 50 - 60 | 8 |
| 60 - 70 | 10 |
| 70 - 80 | 12 |
| 80 - 90 | 16 |
| 90 - 100 | 18 |
| 100 - 110 | 14 |
| 110 - 120 | 12 |
| 120 - 130 | 10 |
(i) Construct the cumulative frequency table
(ii) Draw the cumulative frequency curve on a graph paper and from it, determine the median weight of the apples.
Measures of Central Tendency
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Answer
(i) The cumulative frequency distribution table is as follows:
| Weight (in gm) | Number of apples | Cumulative frequency |
|---|---|---|
| 50 - 60 | 8 | 8 |
| 60 - 70 | 10 | 18 (10 + 8) |
| 70 - 80 | 12 | 30 (18 + 12) |
| 80 - 90 | 16 | 46 (30 + 16) |
| 90 - 100 | 18 | 64 (46 + 18) |
| 100 - 110 | 14 | 78 (64 + 14) |
| 110 - 120 | 12 | 90 (78 + 12) |
| 120 - 130 | 10 | 100 (90 + 10) |
(ii) Steps of construction :
Take 1 cm along x- axis = 10 grams
Take 1 cm along y- axis = 10 units
A kink is drawn near x-axis to show that the scale starts from 50 and not zero. Plot the point (50, 0) as ogive starts from x- axis representing lower limit of first class.
Plot the points (60, 8), (70, 18), (80, 30), (90, 46), (100, 64), (110, 78), (120, 90), (130, 100)
Joint the points by a free hand curve.

Here, n (no, of students) = 100.
To find the median :
Let A be the point on y-axis representing frequency = = 50.
Through A draw a horizontal line to meet the ogive at P. Through P, draw a vertical line to meet the x-axis at M. The abscissa of the points M represents 92.5.
Hence, the median weight is 92.5 gm.
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(iii) Upper quartile (Q3)
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(iii) Upper quartile (Q3)
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(iii) If scoring 85 and more marks is considered as grade one, find the number of students who secured grade one in the examination.
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