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Mathematics

The following table shows the weights (in gm) of a sample of 100 apples, taken from a large consignment:

Weight (in gm)Number of apples
50 - 608
60 - 7010
70 - 8012
80 - 9016
90 - 10018
100 - 11014
110 - 12012
120 - 13010

(i) Construct the cumulative frequency table

(ii) Draw the cumulative frequency curve on a graph paper and from it, determine the median weight of the apples.

Measures of Central Tendency

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Answer

(i) The cumulative frequency distribution table is as follows:

Weight (in gm)Number of applesCumulative frequency
50 - 6088
60 - 701018 (10 + 8)
70 - 801230 (18 + 12)
80 - 901646 (30 + 16)
90 - 1001864 (46 + 18)
100 - 1101478 (64 + 14)
110 - 1201290 (78 + 12)
120 - 13010100 (90 + 10)

(ii) Steps of construction :

  1. Take 1 cm along x- axis = 10 grams

  2. Take 1 cm along y- axis = 10 units

  3. A kink is drawn near x-axis to show that the scale starts from 50 and not zero. Plot the point (50, 0) as ogive starts from x- axis representing lower limit of first class.

  4. Plot the points (60, 8), (70, 18), (80, 30), (90, 46), (100, 64), (110, 78), (120, 90), (130, 100)

  5. Joint the points by a free hand curve.

Draw the cumulative frequency curve on a graph paper and from it, determine the median weight of the apples. Median, Quartiles and Mode, RSA Mathematics Solutions ICSE Class 10.

Here, n (no, of students) = 100.

To find the median :

Let A be the point on y-axis representing frequency = n2=1002\dfrac{\text{n}}{2} = \dfrac{100}{2} = 50.

Through A draw a horizontal line to meet the ogive at P. Through P, draw a vertical line to meet the x-axis at M. The abscissa of the points M represents 92.5.

Hence, the median weight is 92.5 gm.

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