Mathematics
For the following inequations, graph the solution set on the real number line :
-4 ≤ 3x - 1 < 8
Linear Inequations
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Answer
-4 ≤ 3x - 1 < 8
Solving L.H.S. of the equation,
⇒ -4 ≤ 3x - 1
⇒ 3x ≥ -4 + 1
⇒ 3x ≥ -3
⇒ x ≥ -1 ………(i)
Solving R.H.S. of the equation,
⇒ 3x - 1 < 8
⇒ 3x < 8 + 1
⇒ 3x < 9
⇒ x < 3 ………(ii)
From (i) and (ii) we get,
-1 ≤ x < 3.
∴ Solution set = {-1 ≤ x < 3 : x ∈ R }
Solution on the number line is :
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Related Questions
Represent the following inequalities on real number lines :
(i) 2x - 1 < 5
(ii) 3x + 1 ≥ -5
(iii) 2(2x - 3) ≤ 6
(iv) -4 < x < 4
(v) -2 ≤ x < 5
(vi) 8 ≥ x > -3
(vii) -5 < x ≤ -1
For each graph given alongside, write an inequation taking x as the variable :
For the following inequations, graph the solution set on the real number line :
x - 1 < 3 - x ≤ 5
Represent the solution set of each of the following inequalities on the real number line :
4x - 1 > x + 11