$-\dfrac{4}{9}$ divided by $-\dfrac{2}{3}$ gives:

1. $\dfrac{2}{3}$

2. $-\dfrac{2}{3}$

3. $\dfrac{3}{2}$

4. $-\dfrac{3}{2}$

The rational number by which should $\dfrac{1}{2}$ be divided to get $-\dfrac{2}{3}$ is:

1. $\dfrac{3}{4}$

2. $-\dfrac{3}{4}$

3. $\dfrac{4}{3}$

4. $-\dfrac{4}{3}$

The product of two rational numbers is $-7\dfrac{2}{3}$. If one of them is $3\dfrac{5}{6}$, the other number is:

1. 3
2. -3
3. 2
4. -2

(8 ÷ 3) ÷ (3 ÷ 8) is equal to:

1. $\dfrac{64}{9}$

2. $\dfrac{9}{64}$

3. 1

4. none of the above