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Mathematics

For three rational numbers ab\dfrac{a}{b} , cd\dfrac{c}{d} and ef\dfrac{e}{f}, we have:

  1. ab−(cd−ef)=ab−cd+ef\dfrac{a}{b} - \Big(\dfrac{c}{d} - \dfrac{e}{f}\Big) = \dfrac{a}{b} - \dfrac{c}{d} + \dfrac{e}{f}

  2. ab−(cd−ef)=ab−cd−ef\dfrac{a}{b} - \Big(\dfrac{c}{d} - \dfrac{e}{f}\Big) = \dfrac{a}{b} - \dfrac{c}{d} - \dfrac{e}{f}

  3. ab+(cd+ef)\dfrac{a}{b} + \Big(\dfrac{c}{d} + \dfrac{e}{f}\Big) ≠ (ab+cd)+ef\Big(\dfrac{a}{b} + \dfrac{c}{d}\Big) + \dfrac{e}{f}

  4. ab+(cd+ef)=(ab+cd)+ab+ef\dfrac{a}{b} + \Big(\dfrac{c}{d} + \dfrac{e}{f}\Big) = \Big(\dfrac{a}{b} + \dfrac{c}{d}\Big) + \dfrac{a}{b} + \dfrac{e}{f}

Rational Numbers

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Answer

ab−(cd−ef)=ab−cd+ef\dfrac{a}{b} - \Big(\dfrac{c}{d} - \dfrac{e}{f}\Big) = \dfrac{a}{b} - \dfrac{c}{d} + \dfrac{e}{f}

Hence, option 1 is correct option.

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