Four grams of caustic soda contains: (a) 6.02 x 10 23 atoms of it (b) 4 g atom of sodium (c) 6.02 x 10 22 molecules (d) 4 moles of NaOH

6.02 × 10 22 molecule Reason Molar mass of NaOH = Na + O + H = 23 + 16 + 1 = 40 g 40 g of NaOH contains 6.022 × 10 23 molecules 4 g of NaOH contains = x 4 = 6.02 × 10 22 molecules

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Chemistry

Four grams of caustic soda contains:
(a) 6.02 x 10²³ atoms of it
(b) 4 g atom of sodium
(c) 6.02 x 10²² molecules
(d) 4 moles of NaOH

Mole Concept

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Answer

6.02 × 10²² molecule

Reason —

Molar mass of NaOH = Na + O + H = 23 + 16 + 1 = 40 g

40 g of NaOH contains 6.022 × 10²³ molecules

∴ 4 g of NaOH contains

= $\dfrac{6.022 \times 10^{23}}{40}$ x 4

= 6.02 × 10²² molecules

Answered By

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Chemistry

Four grams of caustic soda contains:
(a) 6.02 x 10²³ atoms of it
(b) 4 g atom of sodium
(c) 6.02 x 10²² molecules
(d) 4 moles of NaOH

Mole Concept

Answer

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Chemistry

Four grams of caustic soda contains:(a) 6.02 x 1023 atoms of it(b) 4 g atom of sodium(c) 6.02 x 1022 molecules(d) 4 moles of NaOH

Mole Concept

Answer

Related Questions

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Four grams of caustic soda contains:
(a) 6.02 x 10²³ atoms of it
(b) 4 g atom of sodium
(c) 6.02 x 10²² molecules
(d) 4 moles of NaOH

Nitrogen and hydrogen react to form ammonia.
N₂ (g) + 3H₂ (g) ⟶ 2NH₃ (g)
If 1000 g of H₂ react with 2000 g of N₂:
(a) Will any of the two reactants remain unreacted? If yes, which one and what will be it's mass?
(b) Calculate the mass of ammonia (NH₃) that will be formed?

Which of the following weighs the least?
(a) 2 g atom of N
(b) 3 x 10²⁵ atoms of carbon
(c) 1 mole of sulphur
(d) 7 g of silver

The number of molecules in 4.25 g of ammonia is:
(a) 1.0 × 10²³
(b) 1.5 × 10²³
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