Mathematics
From the adjoining figure, we find :
OP = OR
OP = OQ
PQ = PR
PR ≠ PQ
Triangles
11 Likes
Answer
In △ OPQ and △ OPR,
⇒ OP = OP (Common side)
⇒ ∠POQ = ∠POR (Given)
⇒ ∠OQP = ∠ORP (Both equal to 90°)
∴ △ OPQ ≅ △ OPR (By A.A.S. axiom)
We know that,
Corresponding sides of congruent triangle are equal.
∴ PQ = PR.
Hence, Option 3 is the correct option.
Answered By
6 Likes
Related Questions
In triangle ABC; ∠A = 60°, ∠C = 40° and bisector of angle ABC meets side AC at point P. Show that BP = CP.
In the given figure, AB ⊥ BE, EF ⊥ BE, AB = EF and BC = DE, then :
△ ABD ≅ △ EFC
△ ABD ≅ △ FEC
△ ABD ≅ △ ECF
△ ABD ≅ △ CEF
From the given figure, if ∠A = ∠C, we get :
x = 8, y = 16
x = -8, y = 16
x = 16, y = -8
x = 16, y = 8
ABCD is a rectangle. X and Y are points on sides AD and BC respectively such that AX = BY, then :
AY ≠ BX
△ ABX ≅ △ BYA
△ ABX ≅ △ AYB
△ ABX ≅ △ BAY