From the figure (2) given below, find the value of : (i) sin x (ii) cot x (iii) cot^2 x - cosec^2 x (iv) sec y (v) tan^2 y - 1/cos^2y .

In right angled ∆ABD, By pythagoras theorem we get, ⇒ AD 2 = AB 2 + BD 2 ⇒ AD 2 = 3 2 + 4 2 ⇒ AD 2 = 9 + 16 ⇒ AD 2 = 25 ⇒ AD = ⇒ AD = 5 In right angled triangle DBC, By pythagoras theorem we get, ⇒ DC 2 = DB 2 + BC 2 ⇒ 12 2 = 4 2 + BC 2 ⇒ BC 2 = 12 2 - 4 2 ⇒ BC 2 = 144 - 16 ⇒ BC 2 = 128 ⇒ BC = ⇒ BC = . (i) sin x = = . Hence, sin x = . (ii) cot x = = . Hence, cot x = . (iii) cosec x = = . Substituting values in cot 2 x - cosec 2 x we get : Hence, cot 2 x - cosec 2 x = -1. (iv) sec y = = . Hence, sec y = . (v) tan y = = . Given, Hence,

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From the figure (1) given below, find the value of sec θ.

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From the figure (1) given below, find the values of :
(i) 2 sin y - cos y
(ii) 2 sin x - cos x
(iii) 1 - sin x + cos y
(iv) 2 cos x - 3 sin y + 4 tan x

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Mathematics

From the figure (2) given below, find the value of : (i) sin x (ii) cot x (iii) cot^2 x - cosec^2 x (iv) sec y (v) tan^2 y - 1/cos^2y .

Trigonometrical Ratios

Related Questions

From the figure (1) given below, find the value of sec θ.

From the figure (1) given below, find the values of :
(i) 2 sin y - cos y
(ii) 2 sin x - cos x
(iii) 1 - sin x + cos y
(iv) 2 cos x - 3 sin y + 4 tan x

Mathematics

From the figure (2) given below, find the value of : (i) sin x (ii) cot x (iii) cot^2 x - cosec^2 x (iv) sec y (v) tan^2 y - 1/cos^2y .

Trigonometrical Ratios

Related Questions

From the figure (1) given below, find the value of sec θ.

From the figure (1) given below, find the values of :(i) 2 sin y - cos y(ii) 2 sin x - cos x(iii) 1 - sin x + cos y(iv) 2 cos x - 3 sin y + 4 tan x

From the figure (1) given below, find the values of :
(i) 2 sin y - cos y
(ii) 2 sin x - cos x
(iii) 1 - sin x + cos y
(iv) 2 cos x - 3 sin y + 4 tan x