A fruit-seller bought x apples for ₹ 1,200.
(i) Write the cost price of each apple in terms of x.
(ii) If 10 of the apples were rotten and he sold each of the rest at ₹ 3 more than the cost price of each, write the selling price of (x − 10) apples.
(iii) If he made a profit of ₹ 60 in this transaction, form an equation in x and solve it to evaluate x.

Question

A fruit-seller bought x apples for ₹ 1,200.
(i) Write the cost price of each apple in terms of x.
(ii) If 10 of the apples were rotten and he sold each of the rest at ₹ 3 more than the cost price of each, write the selling price of (x − 10) apples.
(iii) If he made a profit of ₹ 60 in this transaction, form an equation in x and solve it to evaluate x.

KnowledgeBoat · Accepted Answer

(i) Given, Cost of x apples = ₹ 1,200 Cost of one apple = ₹ Hence, cost of each apple in terms of x = ₹ . (ii) Given, Fruit-seller sells each apple at ₹ 3 more than the cost price of each. Selling price of each apple = ₹ + 3 Selling price of (x − 10) apples = ₹ Hence, total selling price = ₹ . (iii) Cost price = ₹ 1,200 Profit = ₹ 60 Selling price = Cost price + Profit = 1200 + 60 = ₹ 1,260 Since, Number of apples cannot be negative. Thus, x = 80 Hence, obtained equation x2 - 30x - 4000 = 0 and the value x = 80.

Mathematics

Quadratic Equations

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