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In a genetic experiment, plants with pure round green seeds (RRyy) were crossed with plants with wrinkled yellow seeds (rrYY). 

(a) Show the gametes formed when F1 was self-pollinated.

(b) A total of 144 seeds were produced which developed into saplings.

Show the ratio in which these traits are independently inherited in these 144 sapling.

Genetics

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Answer

Given : Round (R) dominant over wrinkled (r); Yellow (Y) dominant over green (y).

RRyy (round, green) × rrYY (wrinkled, yellow) → F1 : RrYy (round, yellow).

(a) Gametes formed when F1 (RrYy) is self-pollinated

By independent assortment, each F1 produces four types of gametes in equal proportion i.e.,

RrYy x RrYy → RY, Ry, rY, ry

So the self cross is RrYy × RrYy, with both parents making RY, Ry, rY, ry.

(b) Phenotypic ratio among 144 F2 saplings

The dihybrid self gives the classic 9 : 3 : 3 : 1 phenotypic ratio

  • Round Yellow (RY) = 916×144=81\dfrac{9}{16} \times 144 = 81

  • Round Green (R_yy) = 316×144=27\dfrac{3}{16} \times 144 = 27

  • Wrinkled Yellow (rrY_) = 316×144=27\dfrac{3}{16} \times 144 = 27

  • Wrinkled Green (rryy) = 116×144=9\dfrac{1}{16} \times 144 = 9

So, the F2 saplings are in the ratio 9 : 3 : 3 : 1 (Round Yellow : Round Green : Wrinkled Yellow : Wrinkled Green).

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