Chemistry
Give a test to distinguish dilute sulphuric acid from dilute HCl and dilute HNO3.
Answer
Barium chloride (BaCl2) solution reacts with dilute sulphuric acid to give a white ppt. of barium sulphate (BaSO4) but with dil. HCl and dil. HNO3 no white ppt. is produced since BaCl2 and Ba(NO3)2 is soluble in dil. H2SO4.
H2SO4 (dil.) + BaCl2 (aq.) ⟶ 2HCl + BaSO4 ↓ [white ppt. formed]
HNO3 (dil.) + BaCl2 (aq.) ⟶ No ppt.
HCl (dil.) + BaCl2 (aq.) ⟶ No ppt.
Related Questions
State how addition of –
(i) copper
(ii) NaCl
to hot conc. H2SO4 serves as a test for the latter.
Give two tests for dilute sulphuric acid with balanced equations. State why
(i) BaCl2
(ii) Pb(NO3)2
are used for the above tests
State three different chemical compounds other than acids manufactured industrially from sulphuric acid.
Select the correct answer from the choice in brackets.
- The oxidised product obtained when sulphur reacts with conc. H2SO4. [H2S/SO2/H2SO3].
- The dehydrated product obtained when cane sugar reacts with conc. H2SO4. [CO/C/CO2]
- The type of salt formed when excess of caustic soda reacts with sulphuric acid. [acid salt / normal salt]
- The reduced product obtained when hydrogen sulphide reacts with conc. H2SO4. [SO2/S/H2O]
- The salt which reacts with dil. H2SO4 acid to give an insoluble ppt. [Cu(NO3)2/Zn(NO3)2/Pb(NO3)2]