Computer Applications
Give the output of the following code:
String A ="26", B="100";
String D=A+B+"200";
int x= Integer.parseInt(A);
int y = Integer.parseInt(B);
int d = x+y;
System.out.println("Result 1 = " + D);
System.out.println("Result 2 = " + d);
Answer
Output of the above code is:
Result 1 = 26100200
Result 2 = 126
Working
- As A and B are strings so
String D=A+B+"200";joins A, B and "200" storing the string "26100200" in D. - Integer.parseInt() converts strings A and B into their respective numeric values. Thus, x becomes 26 and y becomes 100.
- As Java is case-sensitive so D and d are treated as two different variables.
- Sum of x and y is assigned to d. Thus, d gets a value of 126.
Related Questions
String s1 = "45.50"; String s2 = "54.50"; double d1=Double.parseDouble(s1); double d2=Double.parseDouble(s2); int x= (int)(d1+d2);What is value of x?
What is the method to check whether a character is a letter or digit?
- isDigit(char)
- isLetterOrDigit()
- isLetterOrDigit(char)
- isLETTERorDIGIT(char)
A student is trying to convert the string present in x to a numerical value, so that he can find the square root of the converted value. However the code has an error. Name the error (syntax / logical / runtime). Correct the code so that it compiles and runs correctly.
String x= "25"; int y=Double.parseDouble(x); double r=Math.sqrt(y); System.out.println(r);State the data type and value of res after the following is executed:
char ch = '9'; res= Character.isDigit(ch);