Given : 17 cos θ = 15; find the value of tan θ + 2 sec θ.

Given: 17 cos θ = 15 cos θ = ∴ If length of AC = 17x unit, length of AB = 15x unit. In Δ ABC, ⇒ AC2 = BC2 \+ AB2 (∵ AC is hypotenuse) ⇒ (17x)2 = BC2 \+ (15x)2 ⇒ 289x2 = BC2 \+ 225x2 ⇒ BC2 = 289x2 \- 225x2 ⇒ BC = ⇒ BC = 8x tan θ = sec θ = Now, tan θ + 2 sec θ Hence, tan θ + 2 sec θ = .