Given A = 60° and B = 30°, prove that :
sin (A + B) = sin A cos B + cos A sin B

Question

Given A = 60° and B = 30°, prove that : sin (A + B) = sin A cos B + cos A sin B

KnowledgeBoat · Accepted Answer

sin (A + B) = sin A cos B + cos A sin B L.H.S. = sin (A + B) = sin (60° + 30°) = sin 90° = 1 R.H.S. = sin A cos B + cos A sin B = sin 60° cos 30° + cos 60° sin 30° ∴ L.H.S. = R.H.S. Hence, sin (A + B) = sin A cos B + cos A sin B.

Mathematics

Given A = 60° and B = 30°, prove that :
sin (A + B) = sin A cos B + cos A sin B

Trigonometric Identities

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Given A = 60° and B = 30°, prove that :sin (A + B) = sin A cos B + cos A sin B

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