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Mathematics

Given A = [1423] and B=[4132]\begin{bmatrix}[r] 1 & 4 \ 2 & 3 \end{bmatrix} \text{ and } B = \begin{bmatrix}[r] -4 & -1 \ -3 & -2 \end{bmatrix}

(i) find the matrix 2A + B

(ii) find a matrix C such that :

C + B = [0000]\begin{bmatrix}[r] 0 & 0 \ 0 & 0 \end{bmatrix}

Matrices

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Answer

(i)

2A+B=2[1423]+[4132]=[2846]+[4132]=[2+(4)8+(1)4+(3)6+(2)]=[2714].2A + B = 2\begin{bmatrix}[r] 1 & 4 \ 2 & 3 \end{bmatrix} + \begin{bmatrix}[r] -4 & -1 \ -3 & -2 \end{bmatrix} \\[1em] = \begin{bmatrix}[r] 2 & 8 \ 4 & 6 \end{bmatrix} + \begin{bmatrix}[r] -4 & -1 \ -3 & -2 \end{bmatrix} \\[1em] = \begin{bmatrix}[r] 2 + (-4) & 8 + (-1) \ 4 + (-3) & 6 + (-2) \end{bmatrix} \\[1em] = \begin{bmatrix}[r] -2 & 7 \ 1 & 4 \end{bmatrix}.

Hence, 2A + B = [2714]\begin{bmatrix}[r] -2 & 7 \ 1 & 4 \end{bmatrix}.

(ii) Given,

C+B=[0000]C=[0000]BC=[0000][4132]C=[0(4)0(1)0(3)0(2)]C=[4132].\Rightarrow C + B = \begin{bmatrix}[r] 0 & 0 \ 0 & 0 \end{bmatrix} \\[1em] \Rightarrow C = \begin{bmatrix}[r] 0 & 0 \ 0 & 0 \end{bmatrix} - B \\[1em] \Rightarrow C = \begin{bmatrix}[r] 0 & 0 \ 0 & 0 \end{bmatrix} - \begin{bmatrix}[r] -4 & -1 \ -3 & -2 \end{bmatrix} \\[1em] \Rightarrow C = \begin{bmatrix}[r] 0 - (-4) & 0 - (-1) \ 0 - (-3) & 0 - (-2) \end{bmatrix} \\[1em] \Rightarrow C = \begin{bmatrix}[r] 4 & 1 \ 3 & 2 \end{bmatrix}.

Hence, C = [4132]\begin{bmatrix}[r] 4 & 1 \ 3 & 2 \end{bmatrix}.

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